baseScalar? | public | Scalar | Scalar this scalar extends. | - | - |
constructors | public | Map<string, ScalarConstructor> | - | - | - |
creating? | public | true | If the type is currently being created. | - | BaseType.creating |
decorators | public | DecoratorApplication[] | - | - | DecoratedType.decorators |
derivedScalars | public | Scalar[] | Direct children. This is the reverse relation of See baseScalar | - | - |
entityKind | readonly | "Type" | - | - | BaseType.entityKind |
instantiationParameters? | public | Type[] | - | - | BaseType.instantiationParameters |
isFinished | public | boolean | Reflect if a type has been finished(Decorators have been called). There is multiple reasons a type might not be finished: - a template declaration will not - a template instance that argument that are still template parameters - a template instance that is only partially instantiated(like a templated operation inside a templated interface) | - | BaseType.isFinished |
kind | public | "Scalar" | - | BaseType.kind | - |
name | public | string | - | - | - |
namespace? | public | Namespace | Namespace the scalar was defined in. | - | - |
node? | public | ScalarStatementNode | Node used to construct this type. If the node is undefined it means the type was dynamically built. With typekit for example. | BaseType.node | - |
templateMapper? | public | TypeMapper | - | - | TemplatedTypeBase.templateMapper |
templateNode? | public | Node | - | - | TemplatedTypeBase.templateNode |